| Topic List |
Page List:
1 |
|---|---|
|
crazyisgood 04/09/12 2:50:00 PM #1: |
Use Newton's method to find the real root function, accurate to five decimal places
f(x) = x^5+2x^2+3 How would I go about solving this? I used x[n] +1 = x[n] -(f(x[n]))/(f '(x[n])) So i got f(x)=x^5 +2x^2 +3 f '(x)= 5x^4 +4x Then I plugged it in and got x[n]=(x^5+2x^2+3)/(5x^4+4x) Now I'm stuck what do I do next? Can someone walk me through the steps to the answer? Thank youuu in advance!!!! -- Randomness 30 http://www.misterpoll.com/polls/262902 ... Copied to Clipboard!
|
|
Gwindor 04/09/12 3:00:00 PM #2: |
Have you tried working through the derivatives one at a time?
The formula is a shorter way of doing the derivatives. I think you should work through them one at a time, in order to get a better understanding of the method. -- "What if you just eat vegetarians?"-neonreaper "^ You are what you eat. ^_~"-Koiji ... Copied to Clipboard!
|
|
greengravy294 04/09/12 3:03:00 PM #3: |
Could try using wolfram alpha. That's usually my get out of hw hell free card. Haven't gotten up to that section yet myself so I can't really offer any other advice!
-- "why" ... Copied to Clipboard!
|
| Topic List |
Page List:
1 |