Board 8 > Price is Right stats question...

(+) Yeah! (+)

Assuming everything else is equal, what are the odds of a player on contestant's row winning the bid with each amount of games left?

For example, only playing one game the odds are 25%, what about the about five options?

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If you're asking what I think you're asking, 1 - .75^x

it is always 25%, since its always 4 people competing. your odds never improve or decline

I think

I'm drunk so i dont quite know if im right or just.....drunk

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[This message was deleted at the request of the original poster]

I you have more chances to bid, your odds will improve.

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Who? Me?

I'm having a hard time seeing contestants having an equal chance at winning.

*bids $1 over the last poster*

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>_>

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From: Dr_Football | #004
it is always 25%, since its always 4 people competing. your odds never improve or decline

Even assuming you have a 25% chance each round (which is untrue for char's reasoning), he means the odds of making it through during the course of the show at all.

From: Xuxon | #003
If you're asking what I think you're asking, 1 - .75^x

And this would be correct, assuming an even 25% chance each round. Which, again, is itself untrue, but the quickest way to approximate it.

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gotcha, understand now

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