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FLOUR 12/20/19 9:45:10 PM #1: |
Where [x] is the greatest integer function. Sure it's easy to guess plugging in different numbers. But how do you go about actually proving it?
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LordFarquad1312 12/20/19 9:56:02 PM #2: |
Try boxing it between 2 functions that both have the same limit as x->infty
Unless I'm missing something, the limit should be 1(?) --- The force is my ally "If you are tired of fear from links... Let Kirby's Nightmare protect you." ... Copied to Clipboard!
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Tyranthraxus 12/20/19 10:03:03 PM #3: |
Are you talking about a proof proof or do you just want to solve it?
Because the limit of any undefined formula that evaluates to 0*infinity, infinity/infinity, or 0/0 is equivalent to the limit of it's derivative. So you take dy/dx of x/[x] and then solve for that limit. Repeat again if you must. That requires you to take my word for it. Proving it is much more advanced. --- It says right here in Matthew 16:4 "Jesus doth not need a giant Mecha." https://imgur.com/dQgC4kv ... Copied to Clipboard!
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Tyranthraxus 12/20/19 10:05:57 PM #4: |
LordFarquad1312 posted...
Try boxing it between 2 functions that both have the same limit as x->inftyIf [x] = x you're correct. If [x] = 2x the limit is 1/2, if it's x^2 the limit is 0. --- It says right here in Matthew 16:4 "Jesus doth not need a giant Mecha." https://imgur.com/dQgC4kv ... Copied to Clipboard!
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