Current Events > If you have 30 people in a room, there is a 100% chance of two of them sharing a

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EpicMickeyDrew
03/14/18 10:57:22 PM
#1:


birthday. Maths is crazy
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DarkTransient
03/14/18 10:58:40 PM
#2:


No, there isn't. There's a very, VERY high chance, but not 100%. You need 367 people to have a 100% chance of that. (And that's assuming we only care about the day and month, not the year. If you care about the year too, it gets even trickier.)
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the_cajun88
03/14/18 10:58:50 PM
#3:


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Duwstai
03/14/18 11:50:42 PM
#4:


EpicMickeyDrew posted...
birthday. Maths is crazy

DarkTransient posted...
No, there isn't. There's a very, VERY high chance, but not 100%. You need 367 people to have a 100% chance of that. (And that's assuming we only care about the day and month, not the year. If you care about the year too, it gets even trickier.)

You both need to go back to school.
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CensorErik
03/14/18 11:51:55 PM
#6:


Duwstai posted...
EpicMickeyDrew posted...
birthday. Maths is crazy

DarkTransient posted...
No, there isn't. There's a very, VERY high chance, but not 100%. You need 367 people to have a 100% chance of that. (And that's assuming we only care about the day and month, not the year. If you care about the year too, it gets even trickier.)

You both need to go back to school.

This. Jfc guys.
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LordFarquad1312
03/14/18 11:53:55 PM
#7:


CensorErik posted...
Duwstai posted...
EpicMickeyDrew posted...
birthday. Maths is crazy

DarkTransient posted...
No, there isn't. There's a very, VERY high chance, but not 100%. You need 367 people to have a 100% chance of that. (And that's assuming we only care about the day and month, not the year. If you care about the year too, it gets even trickier.)

You both need to go back to school.

This. Jfc guys.

What? @DarkTransient is correct.
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clyde_frog
03/14/18 11:55:59 PM
#8:


CensorErik posted...
Duwstai posted...
EpicMickeyDrew posted...
birthday. Maths is crazy

DarkTransient posted...
No, there isn't. There's a very, VERY high chance, but not 100%. You need 367 people to have a 100% chance of that. (And that's assuming we only care about the day and month, not the year. If you care about the year too, it gets even trickier.)

You both need to go back to school.

This. Jfc guys.


Why is the second poster wrong? There could be 366 people with all different birthdays in a room. The 367th person has to share one with another person.
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AlephZero
03/14/18 11:57:07 PM
#9:


i fucking love science
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CensorErik
03/14/18 11:57:23 PM
#10:


clyde_frog posted...
CensorErik posted...
Duwstai posted...
EpicMickeyDrew posted...
birthday. Maths is crazy

DarkTransient posted...
No, there isn't. There's a very, VERY high chance, but not 100%. You need 367 people to have a 100% chance of that. (And that's assuming we only care about the day and month, not the year. If you care about the year too, it gets even trickier.)

You both need to go back to school.

This. Jfc guys.


Why is the second poster wrong? Would it need to only be 366 people?

Yes.
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clyde_frog
03/14/18 11:58:46 PM
#11:


CensorErik posted...
clyde_frog posted...
CensorErik posted...
Duwstai posted...
EpicMickeyDrew posted...
birthday. Maths is crazy

DarkTransient posted...
No, there isn't. There's a very, VERY high chance, but not 100%. You need 367 people to have a 100% chance of that. (And that's assuming we only care about the day and month, not the year. If you care about the year too, it gets even trickier.)

You both need to go back to school.

This. Jfc guys.


Why is the second poster wrong? Would it need to only be 366 people?

Yes.


I edited my post. On a leap year there are 366 days, meaning 366 possible birthdays.
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Tyranthraxus
03/14/18 11:58:50 PM
#12:


CensorErik posted...
clyde_frog posted...
CensorErik posted...
Duwstai posted...
EpicMickeyDrew posted...
birthday. Maths is crazy

DarkTransient posted...
No, there isn't. There's a very, VERY high chance, but not 100%. You need 367 people to have a 100% chance of that. (And that's assuming we only care about the day and month, not the year. If you care about the year too, it gets even trickier.)

You both need to go back to school.

This. Jfc guys.


Why is the second poster wrong? Would it need to only be 366 people?

Yes.

Depends on if you count Feb 29 as a separate day. I can see both answers being correct tbh.
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AlabamaLove
03/14/18 11:58:52 PM
#13:


CensorErik posted...
clyde_frog posted...
CensorErik posted...
Duwstai posted...
EpicMickeyDrew posted...
birthday. Maths is crazy

DarkTransient posted...
No, there isn't. There's a very, VERY high chance, but not 100%. You need 367 people to have a 100% chance of that. (And that's assuming we only care about the day and month, not the year. If you care about the year too, it gets even trickier.)

You both need to go back to school.

This. Jfc guys.


Why is the second poster wrong? Would it need to only be 366 people?

Yes.

Nah 367 is right
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LordFarquad1312
03/14/18 11:58:54 PM
#14:


CensorErik posted...
clyde_frog posted...
CensorErik posted...
Duwstai posted...
EpicMickeyDrew posted...
birthday. Maths is crazy

DarkTransient posted...
No, there isn't. There's a very, VERY high chance, but not 100%. You need 367 people to have a 100% chance of that. (And that's assuming we only care about the day and month, not the year. If you care about the year too, it gets even trickier.)

You both need to go back to school.

This. Jfc guys.


Why is the second poster wrong? Would it need to only be 366 people?

Yes.

Leap year. Also, I just did the math, and with 30 people, the probability of 2 people sharing a birthday is about 70%
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Butterfiles
03/14/18 11:59:21 PM
#15:


you need 365.999~ people
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CensorErik
03/15/18 12:01:03 AM
#16:


Ok. Leap year. Lol. Pile on guys.
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CensorErik
03/15/18 12:02:07 AM
#17:


LordFarquad1312 posted...
CensorErik posted...
clyde_frog posted...
CensorErik posted...
Duwstai posted...
EpicMickeyDrew posted...
birthday. Maths is crazy

DarkTransient posted...
No, there isn't. There's a very, VERY high chance, but not 100%. You need 367 people to have a 100% chance of that. (And that's assuming we only care about the day and month, not the year. If you care about the year too, it gets even trickier.)

You both need to go back to school.

This. Jfc guys.


Why is the second poster wrong? Would it need to only be 366 people?

Yes.

Leap year. Also, I just did the math, and with 30 people, the probability of 2 people sharing a birthday is about 70%

Ok, but 70 is not 100, so TC is still wrong regardless.
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#18
Post #18 was unavailable or deleted.
8-bit_Biceps
03/15/18 12:03:35 AM
#19:


Usually the main quip here is that if you're in a room with 23 including yourself, there's over a 50% chance that any two people have the same birthday.
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LordFarquad1312
03/15/18 12:03:42 AM
#20:


CensorErik posted...
Ok, but 70 is not 100, so TC is still wrong regardless.

Yeah, I just wanted a number.
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Dash_Harber
03/15/18 12:04:44 AM
#21:


DarkTransient posted...
No, there isn't. There's a very, VERY high chance, but not 100%. You need 367 people to have a 100% chance of that. (And that's assuming we only care about the day and month, not the year. If you care about the year too, it gets even trickier.)


That's still not a 100% chance. You can't have a 100% chance with a random group.
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LordFarquad1312
03/15/18 12:05:35 AM
#22:


Dash_Harber posted...
DarkTransient posted...
No, there isn't. There's a very, VERY high chance, but not 100%. You need 367 people to have a 100% chance of that. (And that's assuming we only care about the day and month, not the year. If you care about the year too, it gets even trickier.)


That's still not a 100% chance. You can't have a 100% chance with a random group.

Literally no way 367 people can have different birthdays.
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Dash_Harber
03/15/18 12:06:40 AM
#23:


LordFarquad1312 posted...
Dash_Harber posted...
DarkTransient posted...
No, there isn't. There's a very, VERY high chance, but not 100%. You need 367 people to have a 100% chance of that. (And that's assuming we only care about the day and month, not the year. If you care about the year too, it gets even trickier.)


That's still not a 100% chance. You can't have a 100% chance with a random group.

Literally no way 367 people can have different birthdays.


Wait, yes, you are right. My bad, misread the post.
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Unsugarized_Foo
03/15/18 12:09:44 AM
#24:


LordFarquad1312 posted...
Dash_Harber posted...
DarkTransient posted...
No, there isn't. There's a very, VERY high chance, but not 100%. You need 367 people to have a 100% chance of that. (And that's assuming we only care about the day and month, not the year. If you care about the year too, it gets even trickier.)


That's still not a 100% chance. You can't have a 100% chance with a random group.

Literally no way 367 people can have different birthdays.


You have two people born at the same moment on opposite coasts at 12am EST. Everyone argues, then the two decide to be time twins and leave a day open

Duh
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8-bit_Biceps
03/15/18 12:10:45 AM
#25:


"However, 99.9% probability is reached with just 70 people, and 50% probability with 23 people."

https://en.wikipedia.org/wiki/Birthday_problem
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LordFarquad1312
03/15/18 12:10:51 AM
#26:


Unsugarized_Foo posted...
LordFarquad1312 posted...
Dash_Harber posted...
DarkTransient posted...
No, there isn't. There's a very, VERY high chance, but not 100%. You need 367 people to have a 100% chance of that. (And that's assuming we only care about the day and month, not the year. If you care about the year too, it gets even trickier.)


That's still not a 100% chance. You can't have a 100% chance with a random group.

Literally no way 367 people can have different birthdays.


You have two people born at the same moment on opposite coasts at 12am EST. Everyone argues, then the two decide to be time twins and leave a day open

Duh

Then they share a birthday....
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Unsugarized_Foo
03/15/18 12:11:45 AM
#27:


LordFarquad1312 posted...
Unsugarized_Foo posted...
LordFarquad1312 posted...
Dash_Harber posted...
DarkTransient posted...
No, there isn't. There's a very, VERY high chance, but not 100%. You need 367 people to have a 100% chance of that. (And that's assuming we only care about the day and month, not the year. If you care about the year too, it gets even trickier.)


That's still not a 100% chance. You can't have a 100% chance with a random group.

Literally no way 367 people can have different birthdays.


You have two people born at the same moment on opposite coasts at 12am EST. Everyone argues, then the two decide to be time twins and leave a day open

Duh

Then they share a birthday....


But do they?
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LordFarquad1312
03/15/18 12:14:40 AM
#28:


8-bit_Biceps posted...
"However, 99.9% probability is reached with just 70 people, and 50% probability with 23 people."

https://en.wikipedia.org/wiki/Birthday_problem

Just did the math, it checks out! :D
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EpicMickeyDrew
03/15/18 12:20:00 AM
#29:


CensorErik posted...
Leap year. Also, I just did the math, and with 30 people, the probability of 2 people sharing a birthday is about 70%

Ok, but 70 is not 100, so TC is still wrong regardless.

Most of the time there is a 100% chance of them sharing though.
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LordFarquad1312
03/15/18 12:24:56 AM
#30:


EpicMickeyDrew posted...
CensorErik posted...
Leap year. Also, I just did the math, and with 30 people, the probability of 2 people sharing a birthday is about 70%

Ok, but 70 is not 100, so TC is still wrong regardless.

Most of the time there is a 100% chance of them sharing though.

Yeah, 70% of the time, it happens 100% of the times >.>
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CensorErik
03/15/18 12:31:29 AM
#31:


LordFarquad1312 posted...
EpicMickeyDrew posted...
CensorErik posted...
Leap year. Also, I just did the math, and with 30 people, the probability of 2 people sharing a birthday is about 70%

Ok, but 70 is not 100, so TC is still wrong regardless.

Most of the time there is a 100% chance of them sharing though.

Yeah, 70% of the time, it happens 100% of the times >.>

This sounds like a Maddenism. 95% of the game is half mental. Or, Usually the team with the most points wins.
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