Current Events > If .999... = 1 then math is broken

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Damn_Underscore
11/13/17 9:13:25 PM
#1:


say .999... = 1

then .999...998 = .999... = 1, .999...997 = .999...998 = .999... = 1

You can keep going and eventually say 0 = .000...001 = a bunch of numbers = 1

eventually you can even say -infinity = 1

you can also go forward and say 1 = 1.000...001 all the way up to 1 = infinity

so -infinity and infinity, literally the two furthest apart numbers are equal...

if .999... = 1 then math is broken
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frozenshock
11/13/17 9:14:39 PM
#2:


Well 0.999... + 0.0000....1 = 1
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MutantJohn
11/13/17 9:16:13 PM
#3:


.9...8 is a finite number. .999... is a number with infinite precision.

Basically, lol no rational numbers
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Hey
11/13/17 9:16:52 PM
#4:


MutantJohn posted...
.9...8 is a finite number. .999... is a number with infinite precision.

Basically, lol no rational numbers

Thats not true
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Anteaterking
11/13/17 9:18:26 PM
#6:


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Kaname_Madoka
11/13/17 9:19:59 PM
#7:


Anteaterking posted...
.999....8 is not a real number.

This
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frozenshock
11/13/17 9:24:40 PM
#8:


Kaname_Madoka posted...
Anteaterking posted...
.999....8 is not a real number.

This


Well it's an infinite number of nines followed by an 8.

If you don't understand this then I guess you probably don't know diffegral calculus.
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frozenshock
11/13/17 9:26:09 PM
#10:


RouUvLZ
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Mal_Fet
11/13/17 9:27:56 PM
#11:


Damn_Underscore posted...
then .999...998

No such number. Not even in theory.
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weapon_d00d816
11/13/17 9:31:23 PM
#12:


You can't have an infinite string of decimal places followed by a finite stopping point.
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Doe
11/14/17 4:56:06 PM
#13:


Do people hear themselves? "an infinite number of 9s.... Ending with an 8."

That is by definition a finite number because it terminates. You cannot point at the final number of an infinite number or decimal.
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Unsugarized_Foo
11/14/17 5:04:27 PM
#14:


Just using this logic:

If .999... = .999...998 = 1, then that would mean that there is no number small enough to add to .999...998 in order to make it .999...

To do this, lets add the smallest number which is .0...1, add it to .999... and .999...998.

so we have .999... + .0...1 = 1
then .999...998... +.0...1 = .999...

Since we know .999... = 1, then adding the smallest number to each number has given us the same number. Therefore .999...998 is equal to .999..., which is also equal to 1

Its simple Mathmemeatics
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ZMythos
11/14/17 5:06:04 PM
#15:


MutantJohn posted...
.9...8 is a finite number. .999... is a number with infinite precision.

Basically, lol no rational numbers

but both of those are rational
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Solid Snake07
11/14/17 5:07:07 PM
#16:


It doesn't equal one, it's approximately one
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Paragon21XX
11/14/17 5:08:02 PM
#17:


frozenshock posted...
Kaname_Madoka posted...
Anteaterking posted...
.999....8 is not a real number.

This


Well it's an infinite number of nines followed by an 8.

If you don't understand this then I guess you probably don't know diffegral calculus.

I don't believe you truly understand the meaning of the word "infinite."
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ThirdGender
11/14/17 5:08:37 PM
#18:


No means yes.
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Doe
11/14/17 5:09:00 PM
#19:


Solid Snake07 posted...
It doesn't equal one, it's approximately one

Yes, it does equal 1. They are different notations. It is easily provable.

For example:
1/3 = .333333..
2/3 = .666666...
1 = 3/3 = .99999...
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ChromaticAngel
11/14/17 5:11:51 PM
#20:


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Eevee-Trainer
11/14/17 5:22:20 PM
#21:


This is what happens when people who didn't take a 300-level math course or two in number theory try to pretend they did.
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Rikiaz
11/14/17 5:28:52 PM
#22:


Jesus christ not this stupid argument again.
.999... does, in fact, equal 1. No matter whether your mind can grasp that concept or not.
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