LogFAQs > #933172511

LurkerFAQs, Active DB, DB1, DB2, DB3, DB4, DB5, Database 6 ( 01.01.2020-07.18.2020 ), DB7, DB8, DB9, DB10, DB11, DB12, Clear
Topic List
Page List: 1
TopicStatistics question
wolfy42
01/19/20 11:28:51 AM
#8:


Sahuagin posted...
that is interesting.

there's only a 1/4096 chance of being able to pay only $36 with the $3 option

there's only a ~1/600,000 chance of being able to pay only $24 with the $2 option
I don't know how to calculate $26-$36 with the $2 option

even so, all else being equal, it is an advantage


Yeah, as long as it's actualy 1/3 and not 33%...as the .3333333% would make a different that would offset the small chance to basically get all 12 with the $2 method in 18 or less tries (which is impossible to beat with the $3 method).

As long as it's 1/3 though, that actually comes out to be a somewhat possible chance considering you only end up needing 2/3rds of them to succeed. I am not doing the math in my head no way, but it's a good enough chance to make it better (but again only if it's actually 1/3).

---
Agatha "Your naked and they are nuns, it's not your eyes they're not looking at."
Glowing Elephant "Stonehedge was a sex thing."
... Copied to Clipboard!
Topic List
Page List: 1