LogFAQs > #922908681

PMarth2002 posted...

wolfy42 posted...

I mean, you could roll

1d6 initially, even = 1-10 for the next roll, odd = 11=20

Next roll 1d6 even = 1d5 for the last roll odd = 6-10

Last roll is normal but 6's are re-rolled.

So first roll determines if the result will be between 1-10 or 11-20

Second roll determines if the result will either be A: 1-5 or 6-10 or B: 11-15 or 16-20 (based on the first roll)

Last roll gives the final result within the set parameters.

Every number should be equally as likely with this setup. It's a 50/50 chance for the first roll, the same for the second, and the third roll is a 20% chance for each possibility.

IF even is low and odd is high you need to:

Roll even/even/1 to get a 1

to get a 20 you need to roll odd/odd/5

To roll a 10 you need to roll even/odd/5

To roll a 14 you need to roll odd/even/4

Every outcome is just as likely as every other.

And thats just way more complicated than rolling a d20.

The point is if you don't have a d20 but you need to roll one:)

It's more complicated, but you can make a d6 out of paper way easier (and more accurate) then a d-20, for instance, so if your trying to simulate a d20 in prison for your DnD buddies.....you could use this method.

Also it's not really that complicated if you have different color dice and each dice is determined in advance. You could basically roll them and get the response just about as fast as rolling 1 20 sided dice.

Blue/Green/Red dice....blue determines 1-10/11-20, green 1-5/6-10 and red is the actual number. After doing that for awhile you would read the answer just as fast as a 20 sided when you roll.
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