LogFAQs > #885387297

See this one is messed up. Not because it's hard, it's easy, if you know multiplication/division etc, but because it would be quite difficult for 6 year olds to figure out using shapes (mainly because it's a number on the left side and not objects).

The number on the left is too large to easily break up into objects as well, making this almost impossible for a 6 year old to solve.

If it was a smaller number, this would be fine. If instead of having each circle be worth 9 and each square 27 (think it was), you made each circle be worth 3, and each square worth 9, then a 6 year old might solve it by doing this.

Start the problem off with two circles on the right sight and 6 triangles on the left. The students can place a triangle on each circle until both had 3, and know each circle is worth 3 triangles.

The students could then do the second problem by taking 3 triangles from the left side on each circle, then placing all the traingles that are left on the square, and then making another square and doing the same thing. They could count all the traingles on both square to get the answer.

Without having something they can use as a counter though, it would be very hard for any 1st grade student to solve that problem.
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