Current Events > Which would register more on a scale: A ton of lead or a ton of feathers?

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boink
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https://www.youtube.com/watch?v=uH0hikcwjIA
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RedWhiteBlue posted...

literally a ton of something

Aren't tons just a unit of mass? Is there another ton I'm not thinking of?
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In the figurative version of the word ton the lead would weigh more

Holy crap dictionary.com no longer has it listed as figurative speech 2: a large number or amount

.....okay?
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RedWhiteBlue posted...

Garioshi posted...

.....okay?

Clarify what you mean is what I'm saying. This is akin to topics where the popular vote is wrong and the lessor one wins because of interpretations by the TC.

It's the unit of mass.
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On a scale? The lead would register more because some of the feathers would flutter away
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lilORANG posted...

On a scale? The lead would register more because some of the feathers would flutter away

Not if there's no wind.
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Feathers are vastly more likely to fall off.

Jesus Christ, you guys. No feathers fall off for any reason.
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The feathers.

The amount of pounds are the same, but what you did to those birds will weigh heavy on your heart forever.
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Garioshi posted...

Jesus Christ, you guys. No feathers fall off for any reason.

Then why even ask the question?
A ton is a ton, unless one of them is a tonne or metric ton or something.

Garioshi posted...

lilORANG posted...

On a scale? The lead would register more because some of the feathers would flutter away

Not if there's no wind.

an individual feather is still light af tho. So part of it's mass would be supported by the air in the room.
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lilORANG posted...

Garioshi posted...

lilORANG posted...

On a scale? The lead would register more because some of the feathers would flutter away

Not if there's no wind.

an individual feather is still light af tho. So part of it's mass would be supported by the air in the room.

How does that mean that they'll flutter away?
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Garioshi posted...

lilORANG posted...

Garioshi posted...

lilORANG posted...

On a scale? The lead would register more because some of the feathers would flutter away

Not if there's no wind.

an individual feather is still light af tho. So part of it's mass would be supported by the air in the room.

How does that mean that they'll flutter away?

it doesn't brah. I changed my answer because you changed the terms.
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lilORANG posted...

Garioshi posted...

lilORANG posted...

Garioshi posted...

lilORANG posted...

On a scale? The lead would register more because some of the feathers would flutter away

Not if there's no wind.

an individual feather is still light af tho. So part of it's mass would be supported by the air in the room.

How does that mean that they'll flutter away?

it doesn't brah. I changed my answer because you changed the terms.

Fine, whatever.
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Well considering the way you would compile a ton of feathers is by weighing it in the first place, buoyant force shouldn't be an issue.
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Trick question. Feathers can only be assembled in groups that weigh up to 1840 lbs. Anything more than that and they turn into a bird and peck your eyes out.
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Discounting myself, only one person was right.
Scales measure normal force, which is a force equal to the magnitude of the net force applied to a surface, but in the opposite direction. The net force consists of two components when it comes to our problem: Weight and buoyant force. The weight of an object is just its mass times acceleration due to gravity. In the case of lead and feathers, the weight is the same. However, buoyant force is different. Buoyant force acts directly against weight and is equal to the volume of fluid (in this case air) times the density of the fluid displaced times the acceleration due to gravity. Acceleration due to gravity and the density of the fluid (again, air) are the same, but lead is significantly more dense than feathers, so it takes up less volume. Therefore, the buoyant force on the feathers is greater and it reduces the net force exerted on the scale, reducing the normal force, and therefore reducing the reading.
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What a lame ass topic.
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Now if they were both on a balance...
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lmao bunch of geniuses on ce

lead is heavier so its more duh
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Garioshi posted...

Discounting myself, only one person was right.
Scales measure normal force, which is a force equal to the magnitude of the net force applied to a surface, but in the opposite direction. The net force consists of two components when it comes to our problem: Weight and buoyant force. The weight of an object is just its mass times acceleration due to gravity. In the case of lead and feathers, the weight is the same. However, buoyant force is different. Buoyant force acts directly against weight and is equal to the volume of fluid (in this case air) times the density of the fluid displaced times the acceleration due to gravity. Acceleration due to gravity and the density of the fluid (again, air) are the same, but lead is significantly more dense than feathers, so it takes up less volume. Therefore, the buoyant force on the feathers is greater and it reduces the net force exerted on the scale, reducing the normal force, and therefore reducing the reading.

but in order to get a ton of feathers, you would have to put it on a scale and measure out a ton, which means the buoyant force has already been compensated for.
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MwarriorHiei posted...

but in order to get a ton of feathers, you would have to put it on a scale and measure out a ton, which means the buoyant force has already been compensated for.

No you have to use a balance
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MwarriorHiei posted...

Garioshi posted...

Discounting myself, only one person was right.
Scales measure normal force, which is a force equal to the magnitude of the net force applied to a surface, but in the opposite direction. The net force consists of two components when it comes to our problem: Weight and buoyant force. The weight of an object is just its mass times acceleration due to gravity. In the case of lead and feathers, the weight is the same. However, buoyant force is different. Buoyant force acts directly against weight and is equal to the volume of fluid (in this case air) times the density of the fluid displaced times the acceleration due to gravity. Acceleration due to gravity and the density of the fluid (again, air) are the same, but lead is significantly more dense than feathers, so it takes up less volume. Therefore, the buoyant force on the feathers is greater and it reduces the net force exerted on the scale, reducing the normal force, and therefore reducing the reading.

but in order to get a ton of feathers, you would have to put it on a scale and measure out a ton, which means the buoyant force has already been compensated for.

A ton is a unit of mass, and mass is not measured on a scale.
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What if I'm in the void of space?
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NightRender posted...

What if I'm in the void of space?

You're not. And even if you were, the reading would be incredibly small. And even if you could read it, the lead's reading would still be slightly larger because it takes up less space and its center of mass is closer to the scale than the feathers.
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The feathers because you have to live with the weight of what you did to collect them
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Aren't tons just a unit of mass? Is there another ton I'm not thinking of?

Do lead and feathers have some sort of property that would result in identical masses not resulting in identical weights?
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The feathers.

While both have the same mass, feathers have the capacity to hold air in them while lead doesn't.

The added weight of the air makes the feathers heavier(thus, register more on a scale) than the lead.
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Garioshi posted...

NightRender posted...

What if I'm in the void of space?

You're not. And even if you were, the reading would be incredibly small. And even if you could read it, the lead's reading would still be slightly larger because it takes up less space and its center of mass is closer to the scale than the feathers.

What if the steel was formed into a very, very, very tall rod, standing upright, thus putting its center of mass even farther than the feathers?
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NightRender posted...

Garioshi posted...

NightRender posted...

What if I'm in the void of space?

You're not. And even if you were, the reading would be incredibly small. And even if you could read it, the lead's reading would still be slightly larger because it takes up less space and its center of mass is closer to the scale than the feathers.

What if the steel was formed into a very, very, very tall rod, standing upright, thus putting its center of mass even farther than the feathers?

It would have a weaker reading, then. This is all assuming that the scale and rod would have enough mass to even significantly attract each other in the first place, but that's a topic for another time.
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Garioshi posted...

Discounting myself, only one person was right.
Scales measure normal force, which is a force equal to the magnitude of the net force applied to a surface, but in the opposite direction. The net force consists of two components when it comes to our problem: Weight and buoyant force. The weight of an object is just its mass times acceleration due to gravity. In the case of lead and feathers, the weight is the same. However, buoyant force is different. Buoyant force acts directly against weight and is equal to the volume of fluid (in this case air) times the density of the fluid displaced times the acceleration due to gravity. Acceleration due to gravity and the density of the fluid (again, air) are the same, but lead is significantly more dense than feathers, so it takes up less volume. Therefore, the buoyant force on the feathers is greater and it reduces the net force exerted on the scale, reducing the normal force, and therefore reducing the reading.

Unless of course the scale uses two massive sealed containers consisting of only the materials in a vacuum.

Or if the weighing takes place in a vacuum period with the feathers arranged so that none fall off during the weighing.
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Garioshi posted...

MwarriorHiei posted...

Garioshi posted...

Discounting myself, only one person was right.
Scales measure normal force, which is a force equal to the magnitude of the net force applied to a surface, but in the opposite direction. The net force consists of two components when it comes to our problem: Weight and buoyant force. The weight of an object is just its mass times acceleration due to gravity. In the case of lead and feathers, the weight is the same. However, buoyant force is different. Buoyant force acts directly against weight and is equal to the volume of fluid (in this case air) times the density of the fluid displaced times the acceleration due to gravity. Acceleration due to gravity and the density of the fluid (again, air) are the same, but lead is significantly more dense than feathers, so it takes up less volume. Therefore, the buoyant force on the feathers is greater and it reduces the net force exerted on the scale, reducing the normal force, and therefore reducing the reading.

but in order to get a ton of feathers, you would have to put it on a scale and measure out a ton, which means the buoyant force has already been compensated for.

A ton is a unit of mass, and mass is not measured on a scale.

im pretty sure a ton is 2000 pounds, which is a weight and not a mass.
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A ton of feathers would weigh more because there's some air trapped in the feathers that becomes significant on large enough feather samples
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The best answer is still the third, but nice attempt at a gotcha tc.
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