Board 8 > Is anyone good with polar coordinates and imaginary numbers

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Ayuyu
05/02/12 7:18:00 PM
#1:


From: GaryOak151 | #001
would you should me


Okay

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GaryOak151
05/02/12 7:21:00 PM
#2:


and converting and such

if so would you send me an im at wartank777 i'd appreciate it

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foolm0ron
05/02/12 7:26:00 PM
#3:


theta = arctan(y/x)
r = sqrt(x^2 + y^2)

z = r*e^(theta*i) = r*(cos(theta) + i*sin(theta))

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FL81
05/02/12 7:35:00 PM
#4:


From: foolm0ron | #003
theta = arctan(y/x)
r = sqrt(x^2 + y^2)

z = r*e^(theta*i) = r*(cos(theta) + i*sin(theta))


This + http://www.wolframalpha.com/

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