Current Events > What are positive integers x & y such that x^2-y^4=33 ?

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FLOUR 06/17/22 7:45:00 PM #1:	And how did you derive the solution? --- OK, so what am I doing? Oh, I'm chasing this guy? No, he's chasing me... <cite>FLOUR posted [p:965902081] in What are p... [t:80061677]...</cite> <quote>And how did you derive the solution? </quote> ... Copied to Clipboard!
ChocoboMogALT 06/17/22 7:48:05 PM #2:	Solve for x, plug in for y. Ez --- "We live in a country Hasire.." ~ yosouf06 REVOLVER STAKE! http://img.photobucket.com/albums/v717/ChocoboMog123/AltEisenRChocoboMog.png <cite>ChocoboMogALT posted [p:965902138] in What are p... [t:80061677]...</cite> <quote>Solve for x, plug in for y. Ez </quote> ... Copied to Clipboard!
Steffenfield 06/17/22 7:50:43 PM #3:	x = 17, y = 4 x = 7, y = 2 Can I get a witness? <cite>Steffenfield posted [p:965902207] in What are p... [t:80061677]...</cite> <quote>x = 17, y = 4 x = 7, y = 2 Can I get a witness? </quote> ... Copied to Clipboard!
thronedfire2 06/17/22 8:00:03 PM #5:	Do your own homework --- I could see you, but I couldn't hear you You were holding your hat in the breeze Turning away from me In this moment you were stolen... <cite>thronedfire2 posted [p:965902418] in What are p... [t:80061677]...</cite> <quote>Do your own homework </quote> ... Copied to Clipboard!
pistachio12 06/17/22 8:10:35 PM #6:	Factor to start: ~~(x-y^2)(x+y^2)=33~~ ~~x,y are integers so each factor is an integer.~~ ~~(x-y^2)<(x+y^2)~~ ~~The possible multiples of 33 are 1, 33 and 3, 11.~~ ~~Therefore,~~ ~~x-y^2=3~~ ~~x+y^2=11~~ ~~2x=14~~ ~~x=7, y=2~~ ~~x-y^2=1~~ ~~x+y^2=33~~ ~~2x=34~~ ~~x=17, y=4~~ <cite>pistachio12 posted [p:965902664] in What are p... [t:80061677]...</cite> <quote>Factor to start: (x-y^2)(x+y^2)=33 x,y are integers so each factor is an integer. (x-y^2)<(x+y^2) The possible multiples of 33 are 1, 33 and 3, 11. Therefore, x-y^2=3 x+y^2=11 2x=14 x=7, y=2 x-y^2=1 x+y^2=33 2x=34 x=17, y=4 </quote> ... Copied to Clipboard!
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