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FLOUR 09/15/18 9:14:29 AM #1: |
Where b > 0. That's a huge requirement. There's only one real solution as a result. Why?
Anyways, define k to be the square root of (81c^2+12b^3) Then x = the cube root of [(c/2)+(k/18)] + the cube root of [(c/2)-(k/18)] Is this right? Kind of an ugly solution but it appears to work. If b < 0 then it gets even more ugly as k could be an imaginary number as a result and the computation becomes a disaster. -- --- I wanna be a Hulkamaniac, have fun with my family and friends. ... Copied to Clipboard!
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SageHarpuia 09/15/18 9:15:29 AM #2: |
24
--- "You will pay dearly for your futile resistance!" ... Copied to Clipboard!
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clearaflagrantj 09/15/18 9:16:46 AM #3: |
Man I completed Calc 1-3 and ODE/PDE and I remember none of this shit
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frozenshock 09/15/18 9:17:40 AM #4: |
Yep. Semester started.
--- I don't hate people, people hate me. ... Copied to Clipboard!
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