Current Events > Proof that 0.999...=1

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clearaflagrantj 06/01/17 8:17:17 AM #51:	Look at all the math nerds in this topic. <cite>clearaflagrantj posted [p:880197038] in Proof that... [t:75402802]...</cite> <quote>Look at all the math nerds in this topic.</quote> ... Copied to Clipboard!
ChromaticAngel 06/02/17 2:25:28 PM #52:	scar the 1 posted... Nice to read about p-adic numbers. You don't see that very often. I guess one could say that hyperreals contain numbers that "kind of" lie in-between 1 and 0.999..., but hyperreals aren't so common either. There is no number between 1 and 0.999... because 0.999... IS 1. You're fundamentally asking how many numbers exist between 1 and 1. The answer is 0. They are the same number. I get that people want there to be a number that is infinitely close to 1 but isn't 1, and that number does exist but it is not 0.999... --- https://puu.sh/tcLsT/24f4611235.png <cite>ChromaticAngel posted [p:880280588] in Proof that... [t:75402802]...</cite> <quote><cite>scar the 1 posted...</cite> <quote>Nice to read about p-adic numbers. You don't see that very often. I guess one could say that hyperreals contain numbers that "kind of" lie in-between 1 and 0.999..., but hyperreals aren't so common either.</quote> There is no number between 1 and 0.999... because 0.999... IS 1. You're fundamentally asking how many numbers exist between 1 and 1. The answer is 0. They are the same number. I get that people want there to be a number that is infinitely close to 1 but isn't 1, and that number does exist but it is not 0.999...</quote> ... Copied to Clipboard!
refmon 06/02/17 2:26:27 PM #53:	why stop there? 0.998...=1 --- If you read this signature, then that meant that I had control of what you read for 5 SECONDS!! <cite>refmon posted [p:880280644] in Proof that... [t:75402802]...</cite> <quote>why stop there? 0.998...=1</quote> ... Copied to Clipboard!
ChromaticAngel 06/02/17 2:28:03 PM #54:	refmon posted... why stop there? 0.998...=1 You didn't stop anywhere because you never got to the end of 0.999... --- https://puu.sh/tcLsT/24f4611235.png <cite>ChromaticAngel posted [p:880280739] in Proof that... [t:75402802]...</cite> <quote><cite>refmon posted...</cite> <quote>why stop there? 0.998...=1</quote> You didn't stop anywhere because you never got to the end of 0.999...</quote> ... Copied to Clipboard!
teepan95 06/02/17 2:31:51 PM #55:	Good topic --- http://www.gamefaqs.com/boards/1060-homework-helpers - come drop by! Schnittkraftmeister <cite>teepan95 posted [p:880280913] in Proof that... [t:75402802]...</cite> <quote>Good topic</quote> ... Copied to Clipboard!
Cheese_Crackers 06/02/17 9:08:47 PM #56:	teepan95 posted... Good topic Glad it's well-received. I saw a lot of topics about it but never really saw a meaty discussion about the complex math behind repeating decimals, which is really the best proof of the result. --- Though the fear of death is a common one, the fear of life is a more rational one. <cite>Cheese_Crackers posted [p:880302805] in Proof that... [t:75402802]...</cite> <quote><cite>teepan95 posted...</cite> <quote>Good topic</quote> Glad it's well-received. I saw a lot of topics about it but never really saw a meaty discussion about the complex math behind repeating decimals, which is really the best proof of the result.</quote> ... Copied to Clipboard!
G_G 06/02/17 9:58:42 PM #57:	i dont get it though >_______> why do we arbitrarily decide .999... is 1 but not .999...8 ? --- I am Microwaved_Eggs <cite>G_G posted [p:880305368] in Proof that... [t:75402802]...</cite> <quote>i dont get it though >_______> why do we arbitrarily decide .999... is 1 but not .999...8 ?</quote> ... Copied to Clipboard!
Phantom_Nook 06/02/17 9:59:03 PM #58:	refmon posted... why stop there? 0.998...=1 x = 0.998... 100x = 99.8... 1000x = 998.8... 900x = 899 x = 899/900 --- Posted with GameRaven 3.2 <cite>Phantom_Nook posted [p:880305385] in Proof that... [t:75402802]...</cite> <quote><cite>refmon posted...</cite> <quote>why stop there? 0.998...=1</quote> x = 0.998... 100x = 99.8... 1000x = 998.8... 900x = 899 x = 899/900</quote> ... Copied to Clipboard!
Phantom_Nook 06/02/17 10:00:21 PM #59:	G_G posted... i dont get it though >_______> why do we arbitrarily decide .999... is 1 but not .999...8 ? The periods mean that the 9 is repeating forever. If you have some number of 9's followed by an 8, it's not an infinite sequence. --- Posted with GameRaven 3.2 <cite>Phantom_Nook posted [p:880305461] in Proof that... [t:75402802]...</cite> <quote><cite>G_G posted...</cite> <quote>i dont get it though >_______> why do we arbitrarily decide .999... is 1 but not .999...8 ?</quote> The periods mean that the 9 is repeating forever. If you have some number of 9's followed by an 8, it's not an infinite sequence.</quote> ... Copied to Clipboard!
G_G 06/02/17 10:01:49 PM #60:	thats not what i mean im not asking why .999... is 1 and .999...8 isn't, im asking what decides that .999... is 1 instead of .999... being .999...8 why do we round up --- I am Microwaved_Eggs <cite>G_G posted [p:880305551] in Proof that... [t:75402802]...</cite> <quote>thats not what i mean im not asking why .999... is 1 and .999...8 isn't, im asking what decides that .999... is 1 instead of .999... being .999...8 why do we round up</quote> ... Copied to Clipboard!
Steelers 06/02/17 10:05:26 PM #61:	No whole numbers exist between one and two, are they the same number <cite>Steelers posted [p:880305711] in Proof that... [t:75402802]...</cite> <quote>No whole numbers exist between one and two, are they the same number</quote> ... Copied to Clipboard!
G_G 06/02/17 10:06:00 PM #62:	i dont know <_< im not very good at math, i just dont understand where the line comes from --- I am Microwaved_Eggs <cite>G_G posted [p:880305739] in Proof that... [t:75402802]...</cite> <quote>i dont know <_< im not very good at math, i just dont understand where the line comes from</quote> ... Copied to Clipboard!
Cheese_Crackers 06/02/17 10:26:23 PM #63:	G_G posted... thats not what i mean im not asking why .999... is 1 and .999...8 isn't, im asking what decides that .999... is 1 instead of .999... being .999...8 why do we round up What do you mean by .999...8? An infinite sequence of 9s followed by an 8? That doesn't exist because then the sequence of 9s isn't infinite. The fact that .999...=1 isn't because of rounding up. It's true that .99999999 would be rounded up to 1 in most circumstances, but .999... is a different creature. It's the difference between a finite string of 9s and an infinite one. The only way to talk about an infinite beast like .999... equaling anything is to consider what happens with an extremely long but finite string of 9s, and try to notice a value that these numbers become closer to. In this case, we would consider the following list: .9 .99 .999 .9999 .99999 .999999 .9999999 ...and so on. Maybe you can see that these values, with each iteration, are becoming arbitrarily close to 1. Of course no entry in this list will be 1, but if you want to consider the "limit" of the list - that is, an infinite string of 9s - then you need to consider what value the list entries are becoming arbitrarily close to. --- Though the fear of death is a common one, the fear of life is a more rational one. <cite>Cheese_Crackers posted [p:880306813] in Proof that... [t:75402802]...</cite> <quote><cite>G_G posted...</cite> <quote>thats not what i mean im not asking why .999... is 1 and .999...8 isn't, im asking what decides that .999... is 1 instead of .999... being .999...8 why do we round up</quote> What do you mean by .999...8? An infinite sequence of 9s followed by an 8? That doesn't exist because then the sequence of 9s isn't infinite. The fact that .999...=1 isn't because of rounding up. It's true that .99999999 would be rounded up to 1 in most circumstances, but .999... is a different creature. It's the difference between a finite string of 9s and an infinite one. The only way to talk about an infinite beast like .999... equaling anything is to consider what happens with an extremely long but finite string of 9s, and try to notice a value that these numbers become closer to. In this case, we would consider the following list: .9 .99 .999 .9999 .99999 .999999 .9999999 ...and so on. Maybe you can see that these values, with each iteration, are becoming arbitrarily close to 1. Of course no entry in this list will be 1, but if you want to consider the "limit" of the list - that is, an infinite string of 9s - then you need to consider what value the list entries are becoming arbitrarily close to.</quote> ... Copied to Clipboard!
Mr_Legendia 06/02/17 10:27:30 PM #64:	I'm trying. --- Spirit of Albel-Nox <cite>Mr_Legendia posted [p:880306859] in Proof that... [t:75402802]...</cite> <quote>I'm trying.</quote> ... Copied to Clipboard!
G_G 06/02/17 10:31:32 PM #65:	Cheese_Crackers posted... G_G posted... thats not what i mean im not asking why .999... is 1 and .999...8 isn't, im asking what decides that .999... is 1 instead of .999... being .999...8 why do we round up What do you mean by .999...8? An infinite sequence of 9s followed by an 8? That doesn't exist because then the sequence of 9s isn't infinite. The fact that .999...=1 isn't because of rounding up. It's true that .99999999 would be rounded up to 1 in most circumstances, but .999... is a different creature. It's the difference between a finite string of 9s and an infinite one. The only way to talk about an infinite beast like .999... equaling anything is to consider what happens with an extremely long but finite string of 9s, and try to notice a value that these numbers become closer to. In this case, we would consider the following list: .9 .99 .999 .9999 .99999 .999999 .9999999 ...and so on. Maybe you can see that these values, with each iteration, are becoming arbitrarily close to 1. Of course no entry in this list will be 1, but if you want to consider the "limit" of the list - that is, an infinite string of 9s - then you need to consider what value the list entries are becoming arbitrarily close to. that makes more sense. thanks. sorry for being stupid but is 1.999... 2? --- I am Microwaved_Eggs <cite>G_G posted [p:880307071] in Proof that... [t:75402802]...</cite> <quote><cite>Cheese_Crackers posted...</cite> <quote><cite>G_G posted...</cite> <quote>thats not what i mean im not asking why .999... is 1 and .999...8 isn't, im asking what decides that .999... is 1 instead of .999... being .999...8 why do we round up</quote> What do you mean by .999...8? An infinite sequence of 9s followed by an 8? That doesn't exist because then the sequence of 9s isn't infinite. The fact that .999...=1 isn't because of rounding up. It's true that .99999999 would be rounded up to 1 in most circumstances, but .999... is a different creature. It's the difference between a finite string of 9s and an infinite one. The only way to talk about an infinite beast like .999... equaling anything is to consider what happens with an extremely long but finite string of 9s, and try to notice a value that these numbers become closer to. In this case, we would consider the following list: .9 .99 .999 .9999 .99999 .999999 .9999999 ...and so on. Maybe you can see that these values, with each iteration, are becoming arbitrarily close to 1. Of course no entry in this list will be 1, but if you want to consider the "limit" of the list - that is, an infinite string of 9s - then you need to consider what value the list entries are becoming arbitrarily close to.</quote> that makes more sense. thanks. sorry for being stupid but is 1.999... 2?</quote> ... Copied to Clipboard!
Cheese_Crackers 06/03/17 12:07:11 AM #66:	G_G posted... Cheese_Crackers posted... G_G posted... thats not what i mean im not asking why .999... is 1 and .999...8 isn't, im asking what decides that .999... is 1 instead of .999... being .999...8 why do we round up What do you mean by .999...8? An infinite sequence of 9s followed by an 8? That doesn't exist because then the sequence of 9s isn't infinite. The fact that .999...=1 isn't because of rounding up. It's true that .99999999 would be rounded up to 1 in most circumstances, but .999... is a different creature. It's the difference between a finite string of 9s and an infinite one. The only way to talk about an infinite beast like .999... equaling anything is to consider what happens with an extremely long but finite string of 9s, and try to notice a value that these numbers become closer to. In this case, we would consider the following list: .9 .99 .999 .9999 .99999 .999999 .9999999 ...and so on. Maybe you can see that these values, with each iteration, are becoming arbitrarily close to 1. Of course no entry in this list will be 1, but if you want to consider the "limit" of the list - that is, an infinite string of 9s - then you need to consider what value the list entries are becoming arbitrarily close to. that makes more sense. thanks. sorry for being stupid but is 1.999... 2? You're not being stupid at all. And yeah, 1.999... = 2. It works for any number; 2.34999... = 2.35 I was rewatching Total Drama Island recently and there's an episode where two teams are doing a race or something; the final score is 10 vs 9.999..., and the team with 10 was declared the victor. The correct ruling is that the scores are the same because 9.999... = 10, so it would be a draw. --- Though the fear of death is a common one, the fear of life is a more rational one. <cite>Cheese_Crackers posted [p:880311831] in Proof that... [t:75402802]...</cite> <quote><cite>G_G posted...</cite> <quote><cite>Cheese_Crackers posted...</cite> <quote><cite>G_G posted...</cite> <quote>thats not what i mean im not asking why .999... is 1 and .999...8 isn't, im asking what decides that .999... is 1 instead of .999... being .999...8 why do we round up</quote> What do you mean by .999...8? An infinite sequence of 9s followed by an 8? That doesn't exist because then the sequence of 9s isn't infinite. The fact that .999...=1 isn't because of rounding up. It's true that .99999999 would be rounded up to 1 in most circumstances, but .999... is a different creature. It's the difference between a finite string of 9s and an infinite one. The only way to talk about an infinite beast like .999... equaling anything is to consider what happens with an extremely long but finite string of 9s, and try to notice a value that these numbers become closer to. In this case, we would consider the following list: .9 .99 .999 .9999 .99999 .999999 .9999999 ...and so on. Maybe you can see that these values, with each iteration, are becoming arbitrarily close to 1. Of course no entry in this list will be 1, but if you want to consider the "limit" of the list - that is, an infinite string of 9s - then you need to consider what value the list entries are becoming arbitrarily close to.</quote> that makes more sense. thanks. sorry for being stupid but is 1.999... 2?</quote> You're not being stupid at all. And yeah, 1.999... = 2. It works for any number; 2.34999... = 2.35 I was rewatching Total Drama Island recently and there's an episode where two teams are doing a race or something; the final score is 10 vs 9.999..., and the team with 10 was declared the victor. The correct ruling is that the scores are the same because 9.999... = 10, so it would be a draw.</quote> ... Copied to Clipboard!
FaultyGourry 06/03/17 12:10:16 AM #67:	And yet if you take .001% away from my sandwich it's still going to be missing that .001% and not magically going to be a full sandwich. Chew on that, math! --- You can tell a lot about a man by how he strangles you. "Hypocrisy does not invalidate a point." - S. Rose. https://imgur.com/ZA4vp0y <cite>FaultyGourry posted [p:880311965] in Proof that... [t:75402802]...</cite> <quote>And yet if you take .001% away from my sandwich it's still going to be missing that .001% and not magically going to be a full sandwich. Chew on that, math!</quote> ... Copied to Clipboard!
Albel-Nox 06/03/17 12:19:05 AM #68:	Hardest game yet. Drained, evaded #65/66 and any ninja for now. CONTINUE YES NO ....................... --- How skilled are you really? <cite>Albel-Nox posted [p:880312368] in Proof that... [t:75402802]...</cite> <quote>Hardest game yet. Drained, evaded #65/66 and any ninja for now. CONTINUE YES NO .......................</quote> ... Copied to Clipboard!
G_G 06/03/17 12:21:20 AM #69:	Cheese_Crackers posted... You're not being stupid at all. And yeah, 1.999... = 2. It works for any number; 2.34999... = 2.35 wait it applies for decimals too??? --- I am Microwaved_Eggs <cite>G_G posted [p:880312465] in Proof that... [t:75402802]...</cite> <quote><cite>Cheese_Crackers posted...</cite> <quote>You're not being stupid at all. And yeah, 1.999... = 2. It works for any number; 2.34999... = 2.35</quote> wait it applies for decimals too???</quote> ... Copied to Clipboard!
Cheese_Crackers 06/03/17 12:24:36 AM #70:	G_G posted... Cheese_Crackers posted... You're not being stupid at all. And yeah, 1.999... = 2. It works for any number; 2.34999... = 2.35 wait it applies for decimals too??? Yeah, for the same reason. 2.349 2.3499 2.34999 2.349999 2.3499999 They're getting arbitrarily close to a single value, namely 2.35 Or you could view it as 2.34999... = 2.34 + .00999... = 2.34 + .01 = 2.35, where we applied the same principle as my original post to conclude that .00999... = .01 Basically any infinitely repeating string of nines can be replaced by a single 1 --- Though the fear of death is a common one, the fear of life is a more rational one. <cite>Cheese_Crackers posted [p:880312611] in Proof that... [t:75402802]...</cite> <quote><cite>G_G posted...</cite> <quote><cite>Cheese_Crackers posted...</cite> <quote>You're not being stupid at all. And yeah, 1.999... = 2. It works for any number; 2.34999... = 2.35</quote> wait it applies for decimals too???</quote> Yeah, for the same reason. 2.349 2.3499 2.34999 2.349999 2.3499999 They're getting arbitrarily close to a single value, namely 2.35 Or you could view it as 2.34999... = 2.34 + .00999... = 2.34 + .01 = 2.35, where we applied the same principle as my original post to conclude that .00999... = .01 Basically any infinitely repeating string of nines can be replaced by a single 1</quote> ... Copied to Clipboard!
Mr_Legendia 06/03/17 6:25:37 AM #71:	Lmao!! .999... is more than 1 due to infinitesimal. On!the number line the .999... would go on to to infinity while 1 stays still. That would explain 2.999... being 3, because it can't be less than 3. Or am I off base here? --- Spirit of Albel-Nox <cite>Mr_Legendia posted [p:880321554] in Proof that... [t:75402802]...</cite> <quote>Lmao!! .999... is more than 1 due to infinitesimal. On!the number line the .999... would go on to to infinity while 1 stays still. That would explain 2.999... being 3, because it can't be less than 3. Or am I off base here?</quote> ... Copied to Clipboard!
Mr_Legendia 06/03/17 7:09:06 AM #72:	Yea, Total Drama was on some BS. Thanks for the sandwich, really helped. --- Spirit of Albel-Nox <cite>Mr_Legendia posted [p:880322407] in Proof that... [t:75402802]...</cite> <quote>Yea, Total Drama was on some BS. Thanks for the sandwich, really helped.</quote> ... Copied to Clipboard!
Cheese_Crackers 06/03/17 10:12:19 AM #73:	Mr_Legendia posted... Lmao!! .999... is more than 1 due to infinitesimal. On!the number line the .999... would go on to to infinity while 1 stays still. That would explain 2.999... being 3, because it can't be less than 3. Or am I off base here? I'm not sure which side you're taking here. .999... is exactly equal to 1; infinitesimals aren't part of standard analysis (analysis is the branch of math which deals with continuous processes and limits). If you want to go into non-standard analysis such as hyperreals, then be my guest, but that is definitely not, well, standard. No one will know you're thinking in that way unless you say so. You're right that 2.999... = 3, because 2.999... = 2 + .999... = 2 + 1 = 3 --- Though the fear of death is a common one, the fear of life is a more rational one. <cite>Cheese_Crackers posted [p:880327455] in Proof that... [t:75402802]...</cite> <quote><cite>Mr_Legendia posted...</cite> <quote>Lmao!! .999... is more than 1 due to infinitesimal. On!the number line the .999... would go on to to infinity while 1 stays still. That would explain 2.999... being 3, because it can't be less than 3. Or am I off base here?</quote> I'm not sure which side you're taking here. .999... is exactly equal to 1; infinitesimals aren't part of standard analysis (analysis is the branch of math which deals with continuous processes and limits). If you want to go into non-standard analysis such as hyperreals, then be my guest, but that is definitely not, well, standard. No one will know you're thinking in that way unless you say so. You're right that 2.999... = 3, because 2.999... = 2 + .999... = 2 + 1 = 3</quote> ... Copied to Clipboard!
ChromaticAngel 06/03/17 11:17:21 AM #74:	G_G posted... im not asking why .999... is 1 and .999...8 isn't, im asking what decides that .999... is 1 instead of .999... being .999...8 .999...8 is not a number that exists. Mr_Legendia posted... .999... is more than 1 due to infinitesimal. An infinitesimal is a hyperreal number defined such that 1 / infinitesimal = infinity (or -infinity in the case of a negative infinitesimal). Your theory is nice and all, except 0.999... is a real rational number, not a hyperreal. Hence, 1 - infinitesimal is a nice way of expressing a number that is infinitely close to one but not one, however, that number is not 0.999... as once you add an infinitesimal into the mix, you no longer end up with a real rational number. --- https://puu.sh/tcLsT/24f4611235.png <cite>ChromaticAngel posted [p:880330095] in Proof that... [t:75402802]...</cite> <quote><cite>G_G posted...</cite> <quote>im not asking why .999... is 1 and .999...8 isn't, im asking what decides that .999... is 1 instead of .999... being .999...8 </quote> .999...8 is not a number that exists. <cite>Mr_Legendia posted...</cite> <quote>.999... is more than 1 due to infinitesimal.</quote> An infinitesimal is a hyperreal number defined such that 1 / infinitesimal = infinity (or -infinity in the case of a negative infinitesimal). Your theory is nice and all, except 0.999... is a real rational number, not a hyperreal. Hence, 1 - infinitesimal is a nice way of expressing a number that is infinitely close to one but not one, however, that number is not 0.999... as once you add an infinitesimal into the mix, you no longer end up with a real rational number.</quote> ... Copied to Clipboard!
scar the 1 06/03/17 1:01:09 PM #75:	ChromaticAngel posted... scar the 1 posted... Nice to read about p-adic numbers. You don't see that very often. I guess one could say that hyperreals contain numbers that "kind of" lie in-between 1 and 0.999..., but hyperreals aren't so common either. There is no number between 1 and 0.999... because 0.999... IS 1. You're fundamentally asking how many numbers exist between 1 and 1. The answer is 0. They are the same number. I get that people want there to be a number that is infinitely close to 1 but isn't 1, and that number does exist but it is not 0.999... Yes yes, I was being a bit imprecise, hence the "kind of". Point is that hyperreals include the kind of itsy bitsy number that a lot of people are talking about. Kind of like 0.000...1. DISCLAIMER: I again used the phrase kind of. --- Everything has an end, except for the sausage. It has two. <cite>scar the 1 posted [p:880334733] in Proof that... [t:75402802]...</cite> <quote><cite>ChromaticAngel posted...</cite> <quote><cite>scar the 1 posted...</cite> <quote>Nice to read about p-adic numbers. You don't see that very often. I guess one could say that hyperreals contain numbers that "kind of" lie in-between 1 and 0.999..., but hyperreals aren't so common either.</quote> There is no number between 1 and 0.999... because 0.999... IS 1. You're fundamentally asking how many numbers exist between 1 and 1. The answer is 0. They are the same number. I get that people want there to be a number that is infinitely close to 1 but isn't 1, and that number does exist but it is not 0.999...</quote> Yes yes, I was being a bit imprecise, hence the "kind of". Point is that hyperreals include the kind of itsy bitsy number that a lot of people are talking about. Kind of like 0.000...1. DISCLAIMER: I again used the phrase kind of.</quote> ... Copied to Clipboard!
ChromaticAngel 06/03/17 2:14:58 PM #76:	scar the 1 posted... Yes yes, I was being a bit imprecise, hence the "kind of". Point is that hyperreals include the kind of itsy bitsy number that a lot of people are talking about. Kind of like 0.000...1. DISCLAIMER: I again used the phrase kind of. Sure, but an infinitesimal is not something you can write with Arabic numerals. --- https://puu.sh/tcLsT/24f4611235.png <cite>ChromaticAngel posted [p:880338062] in Proof that... [t:75402802]...</cite> <quote><cite>scar the 1 posted...</cite> <quote>Yes yes, I was being a bit imprecise, hence the "kind of". Point is that hyperreals include the kind of itsy bitsy number that a lot of people are talking about. Kind of like 0.000...1. DISCLAIMER: I again used the phrase kind of.</quote> Sure, but an infinitesimal is not something you can write with Arabic numerals.</quote> ... Copied to Clipboard!
Mr_Legendia 06/03/17 5:30:50 PM #77:	I don't think the postulate .999... is 1 is true. But It really is a monster. Absolute infinity, which seems correct, contradicts the postulate of Addictive Inverse. Please bare with me for I cannot translate all the notions or operands for the sets in OP If .999... is 1, and 1 still stays 1, then what is infinity? I ask this because negation. It brought me the idea that Absolute Infinity can only be terminated by another Absolute Infinity. But if .999... is 1, why if I Inverse either number, either way (left or right), I can't negate anything if I switch the results around. Basically, if .999... and 1 real numbers that are the same, why can't -.999... negate 1 or vice versa. Honestly still not sure. --- Spirit of Albel-Nox <cite>Mr_Legendia posted [p:880347643] in Proof that... [t:75402802]...</cite> <quote>I don't think the postulate .999... is 1 is true. But It really is a monster. Absolute infinity, which seems correct, contradicts the postulate of Addictive Inverse. Please bare with me for I cannot translate all the notions or operands for the sets in OP If .999... is 1, and 1 still stays 1, then what is infinity? I ask this because negation. It brought me the idea that Absolute Infinity can only be terminated by another Absolute Infinity. But if .999... is 1, why if I Inverse either number, either way (left or right), I can't negate anything if I switch the results around. Basically, if .999... and 1 real numbers that are the same, why can't -.999... negate 1 or vice versa. Honestly still not sure.</quote> ... Copied to Clipboard!
ChromaticAngel 06/03/17 5:34:31 PM #78:	Mr_Legendia posted... I don't think the postulate .999... is 1 is true. But It really is a monster. Absolute infinity, which seems correct, contradicts the postulate of Addictive Inverse. Please bare with me for I cannot translate all the notions or operands for the sets in OP If .999... is 1, and 1 still stays 1, then what is infinity? I ask this because negation. It brought me the idea that Absolute Infinity can only be terminated by another Absolute Infinity. But if .999... is 1, why if I Inverse either number, either way (left or right), I can't negate anything if I switch the results around. Basically, if .999... and 1 real numbers that are the same, why can't -.999... negate 1 or vice versa. Honestly still not sure. -0.999... = -1 --- https://puu.sh/tcLsT/24f4611235.png <cite>ChromaticAngel posted [p:880347828] in Proof that... [t:75402802]...</cite> <quote><cite>Mr_Legendia posted...</cite> <quote>I don't think the postulate .999... is 1 is true. But It really is a monster. Absolute infinity, which seems correct, contradicts the postulate of Addictive Inverse. Please bare with me for I cannot translate all the notions or operands for the sets in OP If .999... is 1, and 1 still stays 1, then what is infinity? I ask this because negation. It brought me the idea that Absolute Infinity can only be terminated by another Absolute Infinity. But if .999... is 1, why if I Inverse either number, either way (left or right), I can't negate anything if I switch the results around. Basically, if .999... and 1 real numbers that are the same, why can't -.999... negate 1 or vice versa. Honestly still not sure.</quote> -0.999... = -1</quote> ... Copied to Clipboard!
Mr_Legendia 06/03/17 6:11:02 PM #79:	I don't wanna go to hell. --- Spirit of Albel-Nox <cite>Mr_Legendia posted [p:880349735] in Proof that... [t:75402802]...</cite> <quote>I don't wanna go to hell.</quote> ... Copied to Clipboard!
Mr_Legendia 06/03/17 6:21:04 PM #80:	I've cried so long. Everyone is evil at this point, huh? --- Spirit of Albel-Nox <cite>Mr_Legendia posted [p:880350249] in Proof that... [t:75402802]...</cite> <quote>I've cried so long. Everyone is evil at this point, huh?</quote> ... Copied to Clipboard!
Albel-Nox 06/03/17 6:32:53 PM #81:	WAIT! I did finally figure it out. LMAO. Sooooooo simple. ~~It's NOT and never ever will be.~~ That was cool too, I guess. And PS. Calculus SUCKS! --- How skilled are you really? <cite>Albel-Nox posted [p:880350907] in Proof that... [t:75402802]...</cite> <quote>WAIT! I did finally figure it out. LMAO. Sooooooo simple. It's NOT and never ever will be. That was cool too, I guess. And PS. Calculus SUCKS!</quote> ... Copied to Clipboard!
Mr_Legendia 06/04/17 12:51:08 PM #82:	So that 0.1 is what that 999... can never get, I get it. Well if Jon is practically a 1 and logically a 2, I'm the inverse of both. Life is truly a game, and its mastery only requires attention. --- Spirit of Albel-Nox <cite>Mr_Legendia posted [p:880391745] in Proof that... [t:75402802]...</cite> <quote>So that 0.1 is what that 999... can never get, I get it. Well if Jon is practically a 1 and logically a 2, I'm the inverse of both. Life is truly a game, and its mastery only requires attention.</quote> ... Copied to Clipboard!
Hexagon 06/04/17 1:33:31 PM #83:	Cheese_Crackers posted... It depends on how pedantic you're feeling. Writing down 0.333... = 1/3 isn't a given statement, it requires its own proof. Is long division considered a proof now? It's like saying 2 times 5 equals 10 requires proof. Sounds silly to me. <cite>Hexagon posted [p:880393810] in Proof that... [t:75402802]...</cite> <quote><cite>Cheese_Crackers posted...</cite> <quote> It depends on how pedantic you're feeling. Writing down 0.333... = 1/3 isn't a given statement, it requires its own proof. </quote> Is long division considered a proof now? It's like saying 2 times 5 equals 10 requires proof. Sounds silly to me.</quote> ... Copied to Clipboard!
TheFuzz3451 06/04/17 11:15:17 PM #84:	Are people itt trolling or just stupid --- You're only as sick as your secrets, but the truth shall set you free. The truth is the truth, so all you can do is live with it. <cite>TheFuzz3451 posted [p:880427373] in Proof that... [t:75402802]...</cite> <quote>Are people itt trolling or just stupid</quote> ... Copied to Clipboard!
MutantJohn 06/05/17 3:33:42 PM #85:	TheFuzz3451 posted... Are people itt trolling or just stupid Exactly. 0.999.... cannot equal 1 --- "Oh, my mother; oh, my friends, ask the angels, will I ever see heaven again?" - Laura Marling <cite>MutantJohn posted [p:880464035] in Proof that... [t:75402802]...</cite> <quote><cite>TheFuzz3451 posted...</cite> <quote>Are people itt trolling or just stupid</quote> Exactly. 0.999.... cannot equal 1</quote> ... Copied to Clipboard!
tiornys 06/05/17 3:45:53 PM #86:	MutantJohn posted... Exactly. 0.999.... cannot equal 1 Why not? --- http://etrosgate.com/ <cite>tiornys posted [p:880464721] in Proof that... [t:75402802]...</cite> <quote><cite>MutantJohn posted...</cite> <quote>Exactly. 0.999.... cannot equal 1</quote> Why not?</quote> ... Copied to Clipboard!
MutantJohn 06/05/17 3:46:28 PM #87:	tiornys posted... MutantJohn posted... Exactly. 0.999.... cannot equal 1 Why not? Oh, I was trolling lol --- "Oh, my mother; oh, my friends, ask the angels, will I ever see heaven again?" - Laura Marling <cite>MutantJohn posted [p:880464745] in Proof that... [t:75402802]...</cite> <quote><cite>tiornys posted...</cite> <quote><cite>MutantJohn posted...</cite> <quote> Exactly. 0.999.... cannot equal 1</quote> Why not?</quote> Oh, I was trolling lol</quote> ... Copied to Clipboard!
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