LogFAQs > #984079

LurkerFAQs ( 06.29.2011-09.11.2012 ), Active DB, DB1, DB2, DB3, DB4, DB5, DB6, DB7, DB8, DB9, DB10, DB11, DB12, Clear
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TopicQuick entry-level physics question >_>
Gwindor
04/03/12 2:25:00 PM
#2:


To be accurate, the spring force is position dependent, so while it may change over time, it does not nave to.

the spring force is normally given in physics 1 as -kx, where k is the spring constant and x is the position variable.

The work done by the spring force will be the integral of the spring force over the distance traveled.

Then you can set up your integral as Int[Lower bound initial x, Upper bound final x](-kx)(dx)

I'm fairly certain I didn't answer your question, because I don't understand what you're trying to ask.

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