LogFAQs > #938773374

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Topicx/2 + (x^2)/4! + (x^3)/6! + ... + (x^n)/(2n)! = 1
EmbraceOfDeath
05/07/20 2:56:43 PM
#10:


philsov posted...
1....

1/2 + 1/4 + 1/6 + 1/8.............. = 0.99999999999999999999999~ = 1
That's not the series being used here. If x=1, it would be

1/2 + 1/24 + 1/720 + ... + 1/(2n)! , which is going to be less than 1.

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