LogFAQs > #913954615

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Topic	6÷2(1+2)=?
edededdy 12/11/18 3:24:26 PM #87:	HiddenLurker posted... The 2 would be applied to everything in the parenthesis so the formula 62(1+2) Would actually be 6((21)+(22)) Apply order of operations (Pemdas) 6(2+4) 66 = 1 claims order of operations but then ignores order of operations lmfao hahahahah --- Voted best user on CE 2017 hahahahah lmfao <cite>edededdy posted [p:913954615] in 6÷2... [t:77292057]...</cite> <quote><cite>HiddenLurker posted...</cite> <quote>The 2 would be applied to everything in the parenthesis so the formula 62(1+2) Would actually be 6((21)+(22)) Apply order of operations (Pemdas) 6(2+4) 66 = 1</quote> claims order of operations but then ignores order of operations lmfao hahahahah --- Voted best user on CE 2017 hahahahah lmfao</quote> ... Copied to Clipboard!
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