LogFAQs > #905464785

LurkerFAQs, Active DB, DB1, DB2, Database 3 ( 02.21.2018-07.23.2018 ), DB4, DB5, DB6, DB7, DB8, DB9, DB10, DB11, DB12, Clear
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Choco
07/21/18 9:12:21 AM
#32:


@Rika_Furude posted...
Choco posted...
Rika_Furude posted...
50/50

You could only have drawn a ball from box 1 or 2. Since box 3 does not have a gold ball, you can dismiss it entirely from the equation.

The only question now is if you drew a ball from box 1 or 2.

So, its a 50/50 chance.

Not that hard.

please be joking

you have 5 words to explain how i'm wrong, otherwise you're trolling.

5 words aren't enough because you have a fundamental misunderstanding of stochastics

if you draw a ball from the gold+silver box, the chance of getting the gold ball is only 50%

if you draw a ball from the 2gold box, the chance of getting a gold ball is 100%

the boxes themselves have equal probability when we don't know the result of drawing, but since we know a gold ball was drawn, we have more information and know it was more likely the 2gold box

tl;dr: see the post tc made above this one
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