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Topic | Any of ya'll good at linear algebra? |
Eevee-Trainer 04/20/18 6:47:28 PM #10: | I assume the i, j, and k have a little carat above their heads denoting the fact that they're unit vectors? If so, remember that: * i-hat is the vector [1, 0, 0] * j-hat is the vector [0, 1, 0] * k-hat is the vector [0, 0, 1] Applying the scalar rule should get you 4i and 5j, and then you can find their cross product the normal way to find u. Similarly, find the cross product for v by the cross product of j-hat and k-hat. Then you can find u x v and v x u (though you'll want to note the property v x u = -(u x v) to save some time). Seems an unusually roundabout way to go about it though, thought for a second there might have been a typo in the thing. If you need help finding the cross product I can help with that too, though just know it's going to be the whole "find the determinant of a 3x3 matrix" way. --- See me on Discord! ^.^ Eevee's Mystery Dungeon: https://discord.gg/V7hzcXd ... Copied to Clipboard! |
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