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TopicAny of ya'll good at linear algebra?
Eevee-Trainer
04/20/18 6:47:28 PM
#10:


I assume the i, j, and k have a little carat above their heads denoting the fact that they're unit vectors?

If so, remember that:

* i-hat is the vector [1, 0, 0]
* j-hat is the vector [0, 1, 0]
* k-hat is the vector [0, 0, 1]

Applying the scalar rule should get you 4i and 5j, and then you can find their cross product the normal way to find u. Similarly, find the cross product for v by the cross product of j-hat and k-hat. Then you can find u x v and v x u (though you'll want to note the property v x u = -(u x v) to save some time).

Seems an unusually roundabout way to go about it though, thought for a second there might have been a typo in the thing.

If you need help finding the cross product I can help with that too, though just know it's going to be the whole "find the determinant of a 3x3 matrix" way.
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