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| Topic | Given that (2^x) = (5^y) + 1 where x and y are integers... |
| alphapipi 08/21/17 11:17:42 AM #10: | y must be of a form 6k+3 (other than x=1,y=1) due to 2^y having to be equal to (8 modulus 9) for x>4 y must be of a form 54k+27 solutions that I've found so far x=1 y=1 x=2 y=3 given the complexity that y's form increases, I would say that is all of the solutions --- JAFAX 22:June 29th - July 1st , 2018 in Grand Rapids, MI. | http://www.jafax.org | Home of Cosplay Battle Arena: Fight your friends! ... Copied to Clipboard! |
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