| Topic List | Page List: 1 |
|---|---|
| Topic | A divisibility by 11 problem you've probably never seen. |
| Giacomo_Hawkins 11/02/25 9:59:25 PM #24: | PurestProdigy posted... How the fuck do you figure this out without a calculator The difference between s(1) and s(2) is 11, so the remainder from s(2) is the same as the remainder from s(1) (1 / 11). Between s(2) and s(3) is 111. That is one above a number divisible by 11 (110), so the remainder increments by 1 and is now (2 / 11). 1111 is divisible by 11 (1100 is divisible by 11, add 11 to that) so the remainder is the same as before. 11111 is 1 more than a number divisible by 11 (11110), so the remainder is now (3 / 11) Work into the pattern the zeroes from s(10) and s(20) and you'll be able to work your way up to where the remainder is zero, giving you a whole number. --- Will the little voice in the back of my mind screaming "This is a bad idea" please yield the floor. --Mikey Chivalry be hanged, and so will you. ... Copied to Clipboard! |
| Topic List | Page List: 1 |