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LurkerFAQs ( 06.29.2011-09.11.2012 ), Active DB, DB1, DB2, DB3, DB4, DB5, DB6, DB7, DB8, DB9, DB10, DB11, DB12, Clear
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TopicIt has been too long since I've done calculus -_-''
pirate109
05/23/12 3:33:00 PM
#21:


3)

a) f is linear on each segment so this is easy to graph.

b) g(3) is just the integral of a linear function, hopefully he will know how to do this. my answer is 9. bit confused about how to find g'(-12) since iirc g' = f but f is only defined between -2 and 9 so we don't know what f(-12) is, maybe someone else has some input.

c) this is g'(2) = f(2)

d) g' = f is positive on [-2,4] so g is increasing on this interval, and thus the minimum is g(-2).

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